-3(4z-4)=4-(z-1)

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Solution for -3(4z-4)=4-(z-1) equation: 



-3(4z-4)=4-(z-1)

We move all terms to the left:

-3(4z-4)-(4-(z-1))=0

We multiply parentheses

-12z-(4-(z-1))+12=0



We calculate terms in parentheses: -(4-(z-1)), so:

4-(z-1)

determiningTheFunctionDomain
-(z-1)+4

We get rid of parentheses

-z+1+4

We add all the numbers together, and all the variables

-1z+5

Back to the equation:

-(-1z+5)



We get rid of parentheses

-12z+1z-5+12=0

We add all the numbers together, and all the variables

-11z+7=0

We move all terms containing z to the left, all other terms to the right

-11z=-7

z=-7/-11

z=7/11

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