-3(5-4c)=5c+20

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Solution for -3(5-4c)=5c+20 equation: 



-3(5-4c)=5c+20

We move all terms to the left:

-3(5-4c)-(5c+20)=0

We add all the numbers together, and all the variables

-3(-4c+5)-(5c+20)=0

We multiply parentheses

12c-(5c+20)-15=0

We get rid of parentheses

12c-5c-20-15=0

We add all the numbers together, and all the variables

7c-35=0

We move all terms containing c to the left, all other terms to the right

7c=35

c=35/7

c=5

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