-3(5b+1)=6(b-4)

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Solution for -3(5b+1)=6(b-4) equation: 



-3(5b+1)=6(b-4)

We move all terms to the left:

-3(5b+1)-(6(b-4))=0

We multiply parentheses

-15b-(6(b-4))-3=0



We calculate terms in parentheses: -(6(b-4)), so:

6(b-4)

We multiply parentheses

6b-24

Back to the equation:

-(6b-24)



We get rid of parentheses

-15b-6b+24-3=0

We add all the numbers together, and all the variables

-21b+21=0

We move all terms containing b to the left, all other terms to the right

-21b=-21

b=-21/-21

b=1

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