-3(5c+4)+2=2(3-2c)-16

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Solution for -3(5c+4)+2=2(3-2c)-16 equation: 



-3(5c+4)+2=2(3-2c)-16

We move all terms to the left:

-3(5c+4)+2-(2(3-2c)-16)=0

We add all the numbers together, and all the variables

-3(5c+4)-(2(-2c+3)-16)+2=0

We multiply parentheses

-15c-(2(-2c+3)-16)-12+2=0



We calculate terms in parentheses: -(2(-2c+3)-16), so:

2(-2c+3)-16

We multiply parentheses

-4c+6-16

We add all the numbers together, and all the variables

-4c-10

Back to the equation:

-(-4c-10)



We add all the numbers together, and all the variables

-15c-(-4c-10)-10=0

We get rid of parentheses

-15c+4c+10-10=0

We add all the numbers together, and all the variables

-11c=0

c=0/-11

c=0

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