-3(5c+4)+2=2(3-2c)-16

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Solution for -3(5c+4)+2=2(3-2c)-16 equation:



-3(5c+4)+2=2(3-2c)-16
We move all terms to the left:
-3(5c+4)+2-(2(3-2c)-16)=0
We add all the numbers together, and all the variables
-3(5c+4)-(2(-2c+3)-16)+2=0
We multiply parentheses
-15c-(2(-2c+3)-16)-12+2=0
We calculate terms in parentheses: -(2(-2c+3)-16), so:
2(-2c+3)-16
We multiply parentheses
-4c+6-16
We add all the numbers together, and all the variables
-4c-10
Back to the equation:
-(-4c-10)
We add all the numbers together, and all the variables
-15c-(-4c-10)-10=0
We get rid of parentheses
-15c+4c+10-10=0
We add all the numbers together, and all the variables
-11c=0
c=0/-11
c=0

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