-3(5t-3)+7t=2t-2

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Solution for -3(5t-3)+7t=2t-2 equation: 



-3(5t-3)+7t=2t-2

We move all terms to the left:

-3(5t-3)+7t-(2t-2)=0

We add all the numbers together, and all the variables

7t-3(5t-3)-(2t-2)=0

We multiply parentheses

7t-15t-(2t-2)+9=0

We get rid of parentheses

7t-15t-2t+2+9=0

We add all the numbers together, and all the variables

-10t+11=0

We move all terms containing t to the left, all other terms to the right

-10t=-11

t=-11/-10

t=1+1/10

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