-3(5v-2)+v=2(v+5)

Solution for -3(5v-2)+v=2(v+5) equation:

-3(5v-2)+v=2(v+5)

We move all terms to the left:

-3(5v-2)+v-(2(v+5))=0

We add all the numbers together, and all the variables

v-3(5v-2)-(2(v+5))=0

We multiply parentheses

v-15v-(2(v+5))+6=0


We calculate terms in parentheses: -(2(v+5)), so:

2(v+5)

We multiply parentheses

2v+10

Back to the equation:

-(2v+10)


We add all the numbers together, and all the variables

-14v-(2v+10)+6=0

We get rid of parentheses

-14v-2v-10+6=0

We add all the numbers together, and all the variables

-16v-4=0

We move all terms containing v to the left, all other terms to the right

-16v=4

v=4/-16

v=-1/4