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-3(5x-10)x=-66
We move all terms to the left:
-3(5x-10)x-(-66)=0
We add all the numbers together, and all the variables
-3(5x-10)x+66=0
We multiply parentheses
-15x^2+30x+66=0
a = -15; b = 30; c = +66;
Δ = b2-4ac
Δ = 302-4·(-15)·66
Δ = 4860
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{4860}=\sqrt{324*15}=\sqrt{324}*\sqrt{15}=18\sqrt{15}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(30)-18\sqrt{15}}{2*-15}=\frac{-30-18\sqrt{15}}{-30} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(30)+18\sqrt{15}}{2*-15}=\frac{-30+18\sqrt{15}}{-30} $
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