-3(5x-4)+6(2x-7)=3(x+4)-8(2x+7)

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Solution for -3(5x-4)+6(2x-7)=3(x+4)-8(2x+7) equation: 



-3(5x-4)+6(2x-7)=3(x+4)-8(2x+7)

We move all terms to the left:

-3(5x-4)+6(2x-7)-(3(x+4)-8(2x+7))=0

We multiply parentheses

-15x+12x-(3(x+4)-8(2x+7))+12-42=0



We calculate terms in parentheses: -(3(x+4)-8(2x+7)), so:

3(x+4)-8(2x+7)

We multiply parentheses

3x-16x+12-56

We add all the numbers together, and all the variables

-13x-44

Back to the equation:

-(-13x-44)



We add all the numbers together, and all the variables

-3x-(-13x-44)-30=0

We get rid of parentheses

-3x+13x+44-30=0

We add all the numbers together, and all the variables

10x+14=0

We move all terms containing x to the left, all other terms to the right

10x=-14

x=-14/10

x=-1+2/5

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