-3(5y+1)=5(1-3y)-8

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Solution for -3(5y+1)=5(1-3y)-8 equation:


Simplifying
-3(5y + 1) = 5(1 + -3y) + -8

Reorder the terms:
-3(1 + 5y) = 5(1 + -3y) + -8
(1 * -3 + 5y * -3) = 5(1 + -3y) + -8
(-3 + -15y) = 5(1 + -3y) + -8
-3 + -15y = (1 * 5 + -3y * 5) + -8
-3 + -15y = (5 + -15y) + -8

Reorder the terms:
-3 + -15y = 5 + -8 + -15y

Combine like terms: 5 + -8 = -3
-3 + -15y = -3 + -15y

Add '3' to each side of the equation.
-3 + 3 + -15y = -3 + 3 + -15y

Combine like terms: -3 + 3 = 0
0 + -15y = -3 + 3 + -15y
-15y = -3 + 3 + -15y

Combine like terms: -3 + 3 = 0
-15y = 0 + -15y
-15y = -15y

Add '15y' to each side of the equation.
-15y + 15y = -15y + 15y

Combine like terms: -15y + 15y = 0
0 = -15y + 15y

Combine like terms: -15y + 15y = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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