-3(5y-4)+8y=7(y+2)

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Solution for -3(5y-4)+8y=7(y+2) equation:



-3(5y-4)+8y=7(y+2)
We move all terms to the left:
-3(5y-4)+8y-(7(y+2))=0
We add all the numbers together, and all the variables
8y-3(5y-4)-(7(y+2))=0
We multiply parentheses
8y-15y-(7(y+2))+12=0
We calculate terms in parentheses: -(7(y+2)), so:
7(y+2)
We multiply parentheses
7y+14
Back to the equation:
-(7y+14)
We add all the numbers together, and all the variables
-7y-(7y+14)+12=0
We get rid of parentheses
-7y-7y-14+12=0
We add all the numbers together, and all the variables
-14y-2=0
We move all terms containing y to the left, all other terms to the right
-14y=2
y=2/-14
y=-1/7

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