-3(5y-4)+8y=7(y+2)

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Solution for -3(5y-4)+8y=7(y+2) equation: 



-3(5y-4)+8y=7(y+2)

We move all terms to the left:

-3(5y-4)+8y-(7(y+2))=0

We add all the numbers together, and all the variables

8y-3(5y-4)-(7(y+2))=0

We multiply parentheses

8y-15y-(7(y+2))+12=0



We calculate terms in parentheses: -(7(y+2)), so:

7(y+2)

We multiply parentheses

7y+14

Back to the equation:

-(7y+14)



We add all the numbers together, and all the variables

-7y-(7y+14)+12=0

We get rid of parentheses

-7y-7y-14+12=0

We add all the numbers together, and all the variables

-14y-2=0

We move all terms containing y to the left, all other terms to the right

-14y=2

y=2/-14

y=-1/7

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