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-3(5y-4)+9y=6+3(2y-4)
We move all terms to the left:
-3(5y-4)+9y-(6+3(2y-4))=0
We add all the numbers together, and all the variables
9y-3(5y-4)-(6+3(2y-4))=0
We multiply parentheses
9y-15y-(6+3(2y-4))+12=0
We calculate terms in parentheses: -(6+3(2y-4)), so:We add all the numbers together, and all the variables
6+3(2y-4)
determiningTheFunctionDomain 3(2y-4)+6
We multiply parentheses
6y-12+6
We add all the numbers together, and all the variables
6y-6
Back to the equation:
-(6y-6)
-6y-(6y-6)+12=0
We get rid of parentheses
-6y-6y+6+12=0
We add all the numbers together, and all the variables
-12y+18=0
We move all terms containing y to the left, all other terms to the right
-12y=-18
y=-18/-12
y=1+1/2
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