-3(5y-4)+y=-2(y+1)

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Solution for -3(5y-4)+y=-2(y+1) equation: 



-3(5y-4)+y=-2(y+1)

We move all terms to the left:

-3(5y-4)+y-(-2(y+1))=0

We add all the numbers together, and all the variables

y-3(5y-4)-(-2(y+1))=0

We multiply parentheses

y-15y-(-2(y+1))+12=0



We calculate terms in parentheses: -(-2(y+1)), so:

-2(y+1)

We multiply parentheses

-2y-2

Back to the equation:

-(-2y-2)



We add all the numbers together, and all the variables

-14y-(-2y-2)+12=0

We get rid of parentheses

-14y+2y+2+12=0

We add all the numbers together, and all the variables

-12y+14=0

We move all terms containing y to the left, all other terms to the right

-12y=-14

y=-14/-12

y=1+1/6

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