-3(5z-2)-6=-3(7z+5)-3

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Solution for -3(5z-2)-6=-3(7z+5)-3 equation: 



-3(5z-2)-6=-3(7z+5)-3

We move all terms to the left:

-3(5z-2)-6-(-3(7z+5)-3)=0

We multiply parentheses

-15z-(-3(7z+5)-3)+6-6=0



We calculate terms in parentheses: -(-3(7z+5)-3), so:

-3(7z+5)-3

We multiply parentheses

-21z-15-3

We add all the numbers together, and all the variables

-21z-18

Back to the equation:

-(-21z-18)



We add all the numbers together, and all the variables

-15z-(-21z-18)=0

We get rid of parentheses

-15z+21z+18=0

We add all the numbers together, and all the variables

6z+18=0

We move all terms containing z to the left, all other terms to the right

6z=-18

z=-18/6

z=-3

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