-3(6+-8)+-5=9(b+2)+1

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Solution for -3(6+-8)+-5=9(b+2)+1 equation: 



-3(6+-8)+-5=9(b+2)+1

We move all terms to the left:

-3(6+-8)+-5-(9(b+2)+1)=0

We add all the numbers together, and all the variables

-(9(b+2)+1)-5-3(-2)+=0

We add all the numbers together, and all the variables

-(9(b+2)+1)=0



We calculate terms in parentheses: -(9(b+2)+1), so:

9(b+2)+1

We multiply parentheses

9b+18+1

We add all the numbers together, and all the variables

9b+19

Back to the equation:

-(9b+19)



We get rid of parentheses

-9b-19=0

We move all terms containing b to the left, all other terms to the right

-9b=19

b=19/-9

b=-2+1/9

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