-3(6-2y)=5y+10

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Solution for -3(6-2y)=5y+10 equation: 



-3(6-2y)=5y+10

We move all terms to the left:

-3(6-2y)-(5y+10)=0

We add all the numbers together, and all the variables

-3(-2y+6)-(5y+10)=0

We multiply parentheses

6y-(5y+10)-18=0

We get rid of parentheses

6y-5y-10-18=0

We add all the numbers together, and all the variables

y-28=0

We move all terms containing y to the left, all other terms to the right

y=28

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