-3(6-8)-5=9(b+2)+1

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Solution for -3(6-8)-5=9(b+2)+1 equation:


Simplifying
-3(6 + -8) + -5 = 9(b + 2) + 1

Combine like terms: 6 + -8 = -2
-3(-2) + -5 = 9(b + 2) + 1

Multiply -3 * -2
6 + -5 = 9(b + 2) + 1

Combine like terms: 6 + -5 = 1
1 = 9(b + 2) + 1

Reorder the terms:
1 = 9(2 + b) + 1
1 = (2 * 9 + b * 9) + 1
1 = (18 + 9b) + 1

Reorder the terms:
1 = 18 + 1 + 9b

Combine like terms: 18 + 1 = 19
1 = 19 + 9b

Solving
1 = 19 + 9b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-9b' to each side of the equation.
1 + -9b = 19 + 9b + -9b

Combine like terms: 9b + -9b = 0
1 + -9b = 19 + 0
1 + -9b = 19

Add '-1' to each side of the equation.
1 + -1 + -9b = 19 + -1

Combine like terms: 1 + -1 = 0
0 + -9b = 19 + -1
-9b = 19 + -1

Combine like terms: 19 + -1 = 18
-9b = 18

Divide each side by '-9'.
b = -2

Simplifying
b = -2

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