-3(6u-2)+6u=2(u+8)

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Solution for -3(6u-2)+6u=2(u+8) equation: 



-3(6u-2)+6u=2(u+8)

We move all terms to the left:

-3(6u-2)+6u-(2(u+8))=0

We add all the numbers together, and all the variables

6u-3(6u-2)-(2(u+8))=0

We multiply parentheses

6u-18u-(2(u+8))+6=0



We calculate terms in parentheses: -(2(u+8)), so:

2(u+8)

We multiply parentheses

2u+16

Back to the equation:

-(2u+16)



We add all the numbers together, and all the variables

-12u-(2u+16)+6=0

We get rid of parentheses

-12u-2u-16+6=0

We add all the numbers together, and all the variables

-14u-10=0

We move all terms containing u to the left, all other terms to the right

-14u=10

u=10/-14

u=-5/7

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