-3(6u-2)+6u=3(u+4)

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Solution for -3(6u-2)+6u=3(u+4) equation: 



-3(6u-2)+6u=3(u+4)

We move all terms to the left:

-3(6u-2)+6u-(3(u+4))=0

We add all the numbers together, and all the variables

6u-3(6u-2)-(3(u+4))=0

We multiply parentheses

6u-18u-(3(u+4))+6=0



We calculate terms in parentheses: -(3(u+4)), so:

3(u+4)

We multiply parentheses

3u+12

Back to the equation:

-(3u+12)



We add all the numbers together, and all the variables

-12u-(3u+12)+6=0

We get rid of parentheses

-12u-3u-12+6=0

We add all the numbers together, and all the variables

-15u-6=0

We move all terms containing u to the left, all other terms to the right

-15u=6

u=6/-15

u=-2/5

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