-3(6x+4)+30=10(x-1)

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Solution for -3(6x+4)+30=10(x-1) equation: 



-3(6x+4)+30=10(x-1)

We move all terms to the left:

-3(6x+4)+30-(10(x-1))=0

We multiply parentheses

-18x-(10(x-1))-12+30=0



We calculate terms in parentheses: -(10(x-1)), so:

10(x-1)

We multiply parentheses

10x-10

Back to the equation:

-(10x-10)



We add all the numbers together, and all the variables

-18x-(10x-10)+18=0

We get rid of parentheses

-18x-10x+10+18=0

We add all the numbers together, and all the variables

-28x+28=0

We move all terms containing x to the left, all other terms to the right

-28x=-28

x=-28/-28

x=1

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