-3(6y-10)-y=-3(y-2)

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Solution for -3(6y-10)-y=-3(y-2) equation: 



-3(6y-10)-y=-3(y-2)

We move all terms to the left:

-3(6y-10)-y-(-3(y-2))=0

We add all the numbers together, and all the variables

-1y-3(6y-10)-(-3(y-2))=0

We multiply parentheses

-1y-18y-(-3(y-2))+30=0



We calculate terms in parentheses: -(-3(y-2)), so:

-3(y-2)

We multiply parentheses

-3y+6

Back to the equation:

-(-3y+6)



We add all the numbers together, and all the variables

-19y-(-3y+6)+30=0

We get rid of parentheses

-19y+3y-6+30=0

We add all the numbers together, and all the variables

-16y+24=0

We move all terms containing y to the left, all other terms to the right

-16y=-24

y=-24/-16

y=1+1/2

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