-3(6y-2)+2y=2(y+7)

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Solution for -3(6y-2)+2y=2(y+7) equation: 



-3(6y-2)+2y=2(y+7)

We move all terms to the left:

-3(6y-2)+2y-(2(y+7))=0

We add all the numbers together, and all the variables

2y-3(6y-2)-(2(y+7))=0

We multiply parentheses

2y-18y-(2(y+7))+6=0



We calculate terms in parentheses: -(2(y+7)), so:

2(y+7)

We multiply parentheses

2y+14

Back to the equation:

-(2y+14)



We add all the numbers together, and all the variables

-16y-(2y+14)+6=0

We get rid of parentheses

-16y-2y-14+6=0

We add all the numbers together, and all the variables

-18y-8=0

We move all terms containing y to the left, all other terms to the right

-18y=8

y=8/-18

y=-4/9

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