-3(6y-2)+5y=2(y+6)

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Solution for -3(6y-2)+5y=2(y+6) equation: 



-3(6y-2)+5y=2(y+6)

We move all terms to the left:

-3(6y-2)+5y-(2(y+6))=0

We add all the numbers together, and all the variables

5y-3(6y-2)-(2(y+6))=0

We multiply parentheses

5y-18y-(2(y+6))+6=0



We calculate terms in parentheses: -(2(y+6)), so:

2(y+6)

We multiply parentheses

2y+12

Back to the equation:

-(2y+12)



We add all the numbers together, and all the variables

-13y-(2y+12)+6=0

We get rid of parentheses

-13y-2y-12+6=0

We add all the numbers together, and all the variables

-15y-6=0

We move all terms containing y to the left, all other terms to the right

-15y=6

y=6/-15

y=-2/5

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