-3(6y-5)+4y=4(y+6)

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Solution for -3(6y-5)+4y=4(y+6) equation: 



-3(6y-5)+4y=4(y+6)

We move all terms to the left:

-3(6y-5)+4y-(4(y+6))=0

We add all the numbers together, and all the variables

4y-3(6y-5)-(4(y+6))=0

We multiply parentheses

4y-18y-(4(y+6))+15=0



We calculate terms in parentheses: -(4(y+6)), so:

4(y+6)

We multiply parentheses

4y+24

Back to the equation:

-(4y+24)



We add all the numbers together, and all the variables

-14y-(4y+24)+15=0

We get rid of parentheses

-14y-4y-24+15=0

We add all the numbers together, and all the variables

-18y-9=0

We move all terms containing y to the left, all other terms to the right

-18y=9

y=9/-18

y=-1/2

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