-3(7+2x)+3x+-8=(x-6)+5

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Solution for -3(7+2x)+3x+-8=(x-6)+5 equation: 



-3(7+2x)+3x+-8=(x-6)+5

We move all terms to the left:

-3(7+2x)+3x+-8-((x-6)+5)=0

We add all the numbers together, and all the variables

-3(2x+7)+3x-((x-6)+5)-8+=0

We add all the numbers together, and all the variables

3x-3(2x+7)-((x-6)+5)=0

We multiply parentheses

3x-6x-((x-6)+5)-21=0



We calculate terms in parentheses: -((x-6)+5), so:

(x-6)+5

We get rid of parentheses

x-6+5

We add all the numbers together, and all the variables

x-1

Back to the equation:

-(x-1)



We add all the numbers together, and all the variables

-3x-(x-1)-21=0

We get rid of parentheses

-3x-x+1-21=0

We add all the numbers together, and all the variables

-4x-20=0

We move all terms containing x to the left, all other terms to the right

-4x=20

x=20/-4

x=-5

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