-3(7-2j)=12j+51

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Solution for -3(7-2j)=12j+51 equation:



-3(7-2j)=12j+51
We move all terms to the left:
-3(7-2j)-(12j+51)=0
We add all the numbers together, and all the variables
-3(-2j+7)-(12j+51)=0
We multiply parentheses
6j-(12j+51)-21=0
We get rid of parentheses
6j-12j-51-21=0
We add all the numbers together, and all the variables
-6j-72=0
We move all terms containing j to the left, all other terms to the right
-6j=72
j=72/-6
j=-12

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