-3(7-2j)=12j+51

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Solution for -3(7-2j)=12j+51 equation: 



-3(7-2j)=12j+51

We move all terms to the left:

-3(7-2j)-(12j+51)=0

We add all the numbers together, and all the variables

-3(-2j+7)-(12j+51)=0

We multiply parentheses

6j-(12j+51)-21=0

We get rid of parentheses

6j-12j-51-21=0

We add all the numbers together, and all the variables

-6j-72=0

We move all terms containing j to the left, all other terms to the right

-6j=72

j=72/-6

j=-12

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