-3(8x-2)=62+4(-2x+10)

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Solution for -3(8x-2)=62+4(-2x+10) equation: 



-3(8x-2)=62+4(-2x+10)

We move all terms to the left:

-3(8x-2)-(62+4(-2x+10))=0

We multiply parentheses

-24x-(62+4(-2x+10))+6=0



We calculate terms in parentheses: -(62+4(-2x+10)), so:

62+4(-2x+10)

determiningTheFunctionDomain
4(-2x+10)+62

We multiply parentheses

-8x+40+62

We add all the numbers together, and all the variables

-8x+102

Back to the equation:

-(-8x+102)



We get rid of parentheses

-24x+8x-102+6=0

We add all the numbers together, and all the variables

-16x-96=0

We move all terms containing x to the left, all other terms to the right

-16x=96

x=96/-16

x=-6

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