-3(8y+4)-7y=3(y-1)-1

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Solution for -3(8y+4)-7y=3(y-1)-1 equation: 



-3(8y+4)-7y=3(y-1)-1

We move all terms to the left:

-3(8y+4)-7y-(3(y-1)-1)=0

We add all the numbers together, and all the variables

-7y-3(8y+4)-(3(y-1)-1)=0

We multiply parentheses

-7y-24y-(3(y-1)-1)-12=0



We calculate terms in parentheses: -(3(y-1)-1), so:

3(y-1)-1

We multiply parentheses

3y-3-1

We add all the numbers together, and all the variables

3y-4

Back to the equation:

-(3y-4)



We add all the numbers together, and all the variables

-31y-(3y-4)-12=0

We get rid of parentheses

-31y-3y+4-12=0

We add all the numbers together, and all the variables

-34y-8=0

We move all terms containing y to the left, all other terms to the right

-34y=8

y=8/-34

y=-4/17

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