-3(8y-4)=3(1-9y)+10

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Solution for -3(8y-4)=3(1-9y)+10 equation: 



-3(8y-4)=3(1-9y)+10

We move all terms to the left:

-3(8y-4)-(3(1-9y)+10)=0

We add all the numbers together, and all the variables

-3(8y-4)-(3(-9y+1)+10)=0

We multiply parentheses

-24y-(3(-9y+1)+10)+12=0



We calculate terms in parentheses: -(3(-9y+1)+10), so:

3(-9y+1)+10

We multiply parentheses

-27y+3+10

We add all the numbers together, and all the variables

-27y+13

Back to the equation:

-(-27y+13)



We get rid of parentheses

-24y+27y-13+12=0

We add all the numbers together, and all the variables

3y-1=0

We move all terms containing y to the left, all other terms to the right

3y=1

y=1/3

y=1/3

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