-3(9c-4)+8=4(2c-1)

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Solution for -3(9c-4)+8=4(2c-1) equation: 



-3(9c-4)+8=4(2c-1)

We move all terms to the left:

-3(9c-4)+8-(4(2c-1))=0

We multiply parentheses

-27c-(4(2c-1))+12+8=0



We calculate terms in parentheses: -(4(2c-1)), so:

4(2c-1)

We multiply parentheses

8c-4

Back to the equation:

-(8c-4)



We add all the numbers together, and all the variables

-27c-(8c-4)+20=0

We get rid of parentheses

-27c-8c+4+20=0

We add all the numbers together, and all the variables

-35c+24=0

We move all terms containing c to the left, all other terms to the right

-35c=-24

c=-24/-35

c=24/35

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