-3(a-2)+a+3=2(a+1)-(-3)

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Solution for -3(a-2)+a+3=2(a+1)-(-3) equation: 



-3(a-2)+a+3=2(a+1)-(-3)

We move all terms to the left:

-3(a-2)+a+3-(2(a+1)-(-3))=0

We add all the numbers together, and all the variables

a-3(a-2)-(2(a+1)-(-3))+3=0

We multiply parentheses

a-3a-(2(a+1)-(-3))+6+3=0



We calculate terms in parentheses: -(2(a+1)-(-3)), so:

2(a+1)-(-3)

We add all the numbers together, and all the variables

2(a+1)+3

We multiply parentheses

2a+2+3

We add all the numbers together, and all the variables

2a+5

Back to the equation:

-(2a+5)



We add all the numbers together, and all the variables

-2a-(2a+5)+9=0

We get rid of parentheses

-2a-2a-5+9=0

We add all the numbers together, and all the variables

-4a+4=0

We move all terms containing a to the left, all other terms to the right

-4a=-4

a=-4/-4

a=1

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