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-3(a-3)=10-(3a+1)
We move all terms to the left:
-3(a-3)-(10-(3a+1))=0
We multiply parentheses
-3a-(10-(3a+1))+9=0
We calculate terms in parentheses: -(10-(3a+1)), so:We get rid of parentheses
10-(3a+1)
determiningTheFunctionDomain -(3a+1)+10
We get rid of parentheses
-3a-1+10
We add all the numbers together, and all the variables
-3a+9
Back to the equation:
-(-3a+9)
-3a+3a-9+9=0
We add all the numbers together, and all the variables
=0
a=0/1
a=0
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