-3(a-5)+7=11-6(a+2)

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Solution for -3(a-5)+7=11-6(a+2) equation: 



-3(a-5)+7=11-6(a+2)

We move all terms to the left:

-3(a-5)+7-(11-6(a+2))=0

We multiply parentheses

-3a-(11-6(a+2))+15+7=0



We calculate terms in parentheses: -(11-6(a+2)), so:

11-6(a+2)

determiningTheFunctionDomain
-6(a+2)+11

We multiply parentheses

-6a-12+11

We add all the numbers together, and all the variables

-6a-1

Back to the equation:

-(-6a-1)



We add all the numbers together, and all the variables

-3a-(-6a-1)+22=0

We get rid of parentheses

-3a+6a+1+22=0

We add all the numbers together, and all the variables

3a+23=0

We move all terms containing a to the left, all other terms to the right

3a=-23

a=-23/3

a=-7+2/3

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