-3(a-8)=3/10(20a+10)

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Solution for -3(a-8)=3/10(20a+10) equation: 



-3(a-8)=3/10(20a+10)

We move all terms to the left:

-3(a-8)-(3/10(20a+10))=0



Domain of the equation: 10(20a+10))!=0

a∈R



We multiply parentheses

-3a-(3/10(20a+10))+24=0

We multiply all the terms by the denominator


-3a*10(20a+10))-(3+24*10(20a+10))=0

Wy multiply elements

-30a^2(2+240a(2=0

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