-3(b+1)=-35-5b

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Solution for -3(b+1)=-35-5b equation: 



-3(b+1)=-35-5b

We move all terms to the left:

-3(b+1)-(-35-5b)=0

We add all the numbers together, and all the variables

-3(b+1)-(-5b-35)=0

We multiply parentheses

-3b-(-5b-35)-3=0

We get rid of parentheses

-3b+5b+35-3=0

We add all the numbers together, and all the variables

2b+32=0

We move all terms containing b to the left, all other terms to the right

2b=-32

b=-32/2

b=-16

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