-3(b+1)=2(1-b)*

Solution for -3(b+1)=2(1-b)* equation:

-3(b+1)=2(1-b)*

We move all terms to the left:

-3(b+1)-(2(1-b)*)=0

We add all the numbers together, and all the variables

-3(b+1)-(2(-1b+1)*)=0

We multiply parentheses

-3b-(2(-1b+1)*)-3=0


We calculate terms in parentheses: -(2(-1b+1)*), so:

2(-1b+1)*

We multiply parentheses

-2b+2

Back to the equation:

-(-2b+2)


We get rid of parentheses

-3b+2b-2-3=0

We add all the numbers together, and all the variables

-1b-5=0

We move all terms containing b to the left, all other terms to the right

-b=5

b=5/-1

b=-5