-3(b+2)+(7b-3)=0

Solution for -3(b+2)+(7b-3)=0 equation:

Simplifying
-3(b + 2) + (7b + -3) = 0

Reorder the terms:
-3(2 + b) + (7b + -3) = 0
(2 * -3 + b * -3) + (7b + -3) = 0
(-6 + -3b) + (7b + -3) = 0

Reorder the terms:
-6 + -3b + (-3 + 7b) = 0

Remove parenthesis around (-3 + 7b)
-6 + -3b + -3 + 7b = 0

Reorder the terms:
-6 + -3 + -3b + 7b = 0

Combine like terms: -6 + -3 = -9
-9 + -3b + 7b = 0

Combine like terms: -3b + 7b = 4b
-9 + 4b = 0

Solving
-9 + 4b = 0

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '9' to each side of the equation.
-9 + 9 + 4b = 0 + 9

Combine like terms: -9 + 9 = 0
0 + 4b = 0 + 9
4b = 0 + 9

Combine like terms: 0 + 9 = 9
4b = 9

Divide each side by '4'.
b = 2.25

Simplifying
b = 2.25