-3(b+2)+9(b+2)+4(b+2)=-30

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Solution for -3(b+2)+9(b+2)+4(b+2)=-30 equation: 



-3(b+2)+9(b+2)+4(b+2)=-30

We move all terms to the left:

-3(b+2)+9(b+2)+4(b+2)-(-30)=0

We add all the numbers together, and all the variables

-3(b+2)+9(b+2)+4(b+2)+30=0

We multiply parentheses

-3b+9b+4b-6+18+8+30=0

We add all the numbers together, and all the variables

10b+50=0

We move all terms containing b to the left, all other terms to the right

10b=-50

b=-50/10

b=-5

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