-3(b+2)=-3b-6

Solution for -3(b+2)=-3b-6 equation:

Simplifying
-3(b + 2) = -3b + -6

Reorder the terms:
-3(2 + b) = -3b + -6
(2 * -3 + b * -3) = -3b + -6
(-6 + -3b) = -3b + -6

Reorder the terms:
-6 + -3b = -6 + -3b

Add '6' to each side of the equation.
-6 + 6 + -3b = -6 + 6 + -3b

Combine like terms: -6 + 6 = 0
0 + -3b = -6 + 6 + -3b
-3b = -6 + 6 + -3b

Combine like terms: -6 + 6 = 0
-3b = 0 + -3b
-3b = -3b

Add '3b' to each side of the equation.
-3b + 3b = -3b + 3b

Combine like terms: -3b + 3b = 0
0 = -3b + 3b

Combine like terms: -3b + 3b = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.