-3(b+2)=2(4b+2)-b

Solution for -3(b+2)=2(4b+2)-b equation:

Simplifying
-3(b + 2) = 2(4b + 2) + -1b

Reorder the terms:
-3(2 + b) = 2(4b + 2) + -1b
(2 * -3 + b * -3) = 2(4b + 2) + -1b
(-6 + -3b) = 2(4b + 2) + -1b

Reorder the terms:
-6 + -3b = 2(2 + 4b) + -1b
-6 + -3b = (2 * 2 + 4b * 2) + -1b
-6 + -3b = (4 + 8b) + -1b

Combine like terms: 8b + -1b = 7b
-6 + -3b = 4 + 7b

Solving
-6 + -3b = 4 + 7b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-7b' to each side of the equation.
-6 + -3b + -7b = 4 + 7b + -7b

Combine like terms: -3b + -7b = -10b
-6 + -10b = 4 + 7b + -7b

Combine like terms: 7b + -7b = 0
-6 + -10b = 4 + 0
-6 + -10b = 4

Add '6' to each side of the equation.
-6 + 6 + -10b = 4 + 6

Combine like terms: -6 + 6 = 0
0 + -10b = 4 + 6
-10b = 4 + 6

Combine like terms: 4 + 6 = 10
-10b = 10

Divide each side by '-10'.
b = -1

Simplifying
b = -1