-3(b+8)-5=9(b+2)+1

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Solution for -3(b+8)-5=9(b+2)+1 equation:


Simplifying
-3(b + 8) + -5 = 9(b + 2) + 1

Reorder the terms:
-3(8 + b) + -5 = 9(b + 2) + 1
(8 * -3 + b * -3) + -5 = 9(b + 2) + 1
(-24 + -3b) + -5 = 9(b + 2) + 1

Reorder the terms:
-24 + -5 + -3b = 9(b + 2) + 1

Combine like terms: -24 + -5 = -29
-29 + -3b = 9(b + 2) + 1

Reorder the terms:
-29 + -3b = 9(2 + b) + 1
-29 + -3b = (2 * 9 + b * 9) + 1
-29 + -3b = (18 + 9b) + 1

Reorder the terms:
-29 + -3b = 18 + 1 + 9b

Combine like terms: 18 + 1 = 19
-29 + -3b = 19 + 9b

Solving
-29 + -3b = 19 + 9b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-9b' to each side of the equation.
-29 + -3b + -9b = 19 + 9b + -9b

Combine like terms: -3b + -9b = -12b
-29 + -12b = 19 + 9b + -9b

Combine like terms: 9b + -9b = 0
-29 + -12b = 19 + 0
-29 + -12b = 19

Add '29' to each side of the equation.
-29 + 29 + -12b = 19 + 29

Combine like terms: -29 + 29 = 0
0 + -12b = 19 + 29
-12b = 19 + 29

Combine like terms: 19 + 29 = 48
-12b = 48

Divide each side by '-12'.
b = -4

Simplifying
b = -4

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