-3(b-2)-2b=2b+28

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Solution for -3(b-2)-2b=2b+28 equation: 



-3(b-2)-2b=2b+28

We move all terms to the left:

-3(b-2)-2b-(2b+28)=0

We add all the numbers together, and all the variables

-2b-3(b-2)-(2b+28)=0

We multiply parentheses

-2b-3b-(2b+28)+6=0

We get rid of parentheses

-2b-3b-2b-28+6=0

We add all the numbers together, and all the variables

-7b-22=0

We move all terms containing b to the left, all other terms to the right

-7b=22

b=22/-7

b=-3+1/7

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