-3(b-2)=2(1-2b)

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Solution for -3(b-2)=2(1-2b) equation: 



-3(b-2)=2(1-2b)

We move all terms to the left:

-3(b-2)-(2(1-2b))=0

We add all the numbers together, and all the variables

-3(b-2)-(2(-2b+1))=0

We multiply parentheses

-3b-(2(-2b+1))+6=0



We calculate terms in parentheses: -(2(-2b+1)), so:

2(-2b+1)

We multiply parentheses

-4b+2

Back to the equation:

-(-4b+2)



We get rid of parentheses

-3b+4b-2+6=0

We add all the numbers together, and all the variables

b+4=0

We move all terms containing b to the left, all other terms to the right

b=-4

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