-3(b-3)-5(-7b+5)=16

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Solution for -3(b-3)-5(-7b+5)=16 equation: 



-3(b-3)-5(-7b+5)=16

We move all terms to the left:

-3(b-3)-5(-7b+5)-(16)=0

We multiply parentheses

-3b+35b+9-25-16=0

We add all the numbers together, and all the variables

32b-32=0

We move all terms containing b to the left, all other terms to the right

32b=32

b=32/32

b=1

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