-3(b-4)-2(1-4b)=4b+8+1

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Solution for -3(b-4)-2(1-4b)=4b+8+1 equation: 



-3(b-4)-2(1-4b)=4b+8+1

We move all terms to the left:

-3(b-4)-2(1-4b)-(4b+8+1)=0

We add all the numbers together, and all the variables

-3(b-4)-2(-4b+1)-(4b+9)=0

We multiply parentheses

-3b+8b-(4b+9)+12-2=0

We get rid of parentheses

-3b+8b-4b-9+12-2=0

We add all the numbers together, and all the variables

b+1=0

We move all terms containing b to the left, all other terms to the right

b=-1

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