-3(b-4)=27

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Solution for -3(b-4)=27 equation: 



-3(b-4)=27

We move all terms to the left:

-3(b-4)-(27)=0

We multiply parentheses

-3b+12-27=0

We add all the numbers together, and all the variables

-3b-15=0

We move all terms containing b to the left, all other terms to the right

-3b=15

b=15/-3

b=-5

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