-3(b-5)=27+b

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Solution for -3(b-5)=27+b equation: 



-3(b-5)=27+b

We move all terms to the left:

-3(b-5)-(27+b)=0

We add all the numbers together, and all the variables

-3(b-5)-(b+27)=0

We multiply parentheses

-3b-(b+27)+15=0

We get rid of parentheses

-3b-b-27+15=0

We add all the numbers together, and all the variables

-4b-12=0

We move all terms containing b to the left, all other terms to the right

-4b=12

b=12/-4

b=-3

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