-3(b-5)=3

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Solution for -3(b-5)=3 equation: 



-3(b-5)=3

We move all terms to the left:

-3(b-5)-(3)=0

We multiply parentheses

-3b+15-3=0

We add all the numbers together, and all the variables

-3b+12=0

We move all terms containing b to the left, all other terms to the right

-3b=-12

b=-12/-3

b=+4

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