-3(b-8)-5=9(b+2)+1

Solution for -3(b-8)-5=9(b+2)+1 equation:

Simplifying
-3(b + -8) + -5 = 9(b + 2) + 1

Reorder the terms:
-3(-8 + b) + -5 = 9(b + 2) + 1
(-8 * -3 + b * -3) + -5 = 9(b + 2) + 1
(24 + -3b) + -5 = 9(b + 2) + 1

Reorder the terms:
24 + -5 + -3b = 9(b + 2) + 1

Combine like terms: 24 + -5 = 19
19 + -3b = 9(b + 2) + 1

Reorder the terms:
19 + -3b = 9(2 + b) + 1
19 + -3b = (2 * 9 + b * 9) + 1
19 + -3b = (18 + 9b) + 1

Reorder the terms:
19 + -3b = 18 + 1 + 9b

Combine like terms: 18 + 1 = 19
19 + -3b = 19 + 9b

Add '-19' to each side of the equation.
19 + -19 + -3b = 19 + -19 + 9b

Combine like terms: 19 + -19 = 0
0 + -3b = 19 + -19 + 9b
-3b = 19 + -19 + 9b

Combine like terms: 19 + -19 = 0
-3b = 0 + 9b
-3b = 9b

Solving
-3b = 9b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-9b' to each side of the equation.
-3b + -9b = 9b + -9b

Combine like terms: -3b + -9b = -12b
-12b = 9b + -9b

Combine like terms: 9b + -9b = 0
-12b = 0

Divide each side by '-12'.
b = 0

Simplifying
b = 0