-3(b-8)-5=9(b+2)1

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Solution for -3(b-8)-5=9(b+2)1 equation:


Simplifying
-3(b + -8) + -5 = 9(b + 2) * 1

Reorder the terms:
-3(-8 + b) + -5 = 9(b + 2) * 1
(-8 * -3 + b * -3) + -5 = 9(b + 2) * 1
(24 + -3b) + -5 = 9(b + 2) * 1

Reorder the terms:
24 + -5 + -3b = 9(b + 2) * 1

Combine like terms: 24 + -5 = 19
19 + -3b = 9(b + 2) * 1

Reorder the terms:
19 + -3b = 9(2 + b) * 1

Reorder the terms for easier multiplication:
19 + -3b = 9 * 1(2 + b)

Multiply 9 * 1
19 + -3b = 9(2 + b)
19 + -3b = (2 * 9 + b * 9)
19 + -3b = (18 + 9b)

Solving
19 + -3b = 18 + 9b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-9b' to each side of the equation.
19 + -3b + -9b = 18 + 9b + -9b

Combine like terms: -3b + -9b = -12b
19 + -12b = 18 + 9b + -9b

Combine like terms: 9b + -9b = 0
19 + -12b = 18 + 0
19 + -12b = 18

Add '-19' to each side of the equation.
19 + -19 + -12b = 18 + -19

Combine like terms: 19 + -19 = 0
0 + -12b = 18 + -19
-12b = 18 + -19

Combine like terms: 18 + -19 = -1
-12b = -1

Divide each side by '-12'.
b = 0.08333333333

Simplifying
b = 0.08333333333

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