-3(i+5)+(4i+2)=8

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Solution for -3(i+5)+(4i+2)=8 equation:


Simplifying
-3(i + 5) + (4i + 2) = 8

Reorder the terms:
-3(5 + i) + (4i + 2) = 8
(5 * -3 + i * -3) + (4i + 2) = 8
(-15 + -3i) + (4i + 2) = 8

Reorder the terms:
-15 + -3i + (2 + 4i) = 8

Remove parenthesis around (2 + 4i)
-15 + -3i + 2 + 4i = 8

Reorder the terms:
-15 + 2 + -3i + 4i = 8

Combine like terms: -15 + 2 = -13
-13 + -3i + 4i = 8

Combine like terms: -3i + 4i = 1i
-13 + 1i = 8

Solving
-13 + 1i = 8

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '13' to each side of the equation.
-13 + 13 + 1i = 8 + 13

Combine like terms: -13 + 13 = 0
0 + 1i = 8 + 13
1i = 8 + 13

Combine like terms: 8 + 13 = 21
1i = 21

Divide each side by '1'.
i = 21

Simplifying
i = 21

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